Great Bear Resources Ltd. GTBAF

re how big this thing is

[Ivorygull]

Not sure if a total of all the drill holes that flashcash pointed to, makes any sense, or if the figures mean anything, but I totalled them anyway.....

Width 6522.43
Grade 5812

Average width 13.26
Average grade 11.81

I'm sure there are those of you who can say if this does anything to help, or if it is a useless calculation.

Please chime in.

[vestor111]

Nice work IG but is a decimal point missing on the 5813 grade?  Otherwise GBR is soooo undervalued!  YIKES!  Ok 5812 is total of all grades???  Across all sectors? I have never seen a calculation like this.  But WTFDIK???  Is this a common calculation technique or something you cooked up?  Pls enlighten me...I am more of a spectator and not in mining. 

[Ivorygull]

I don't know if the numbers can be used. I just totalled them up and hoped that others could say if the numbers can be used or not.

[Ivorygull]

Here is the table I totalled. I copied all the drill hole results from the link that flashcash had pointed us to earlier on today...   Widths Grade   50.60 0.74   1 27.15  

[Ivorygull]

If we use the quick calculation that Goaweigh used earlier on today, the calculation that I just made, might not be so unreasonable.   Goaweigh 150 metres x 200 metres deep x 100 metres thick. (I presume thickness is width) Strike in Metres 150 Depth in Metres 200 Width in Metres

[goldminer1956]

good work.   at 25.3 Million(M) ounces, I believe properties go for $155 proven and probable oz, so  25.3 M x $155US=$US3.9Billion / 50Million shares = $US 78 per share. whomever sold this property to us can redeem themselves by buying this thing before GBR drills the whole monster and finds 60M ounces. variables  forecast s of gold going to $3000/oz, how deep will this gold go

[Ivorygull]

If those numbers can be utilized, can they then be entered into a formula to get the number of ounces in a given area. I don't know. What do others think? Strike in Metres 4000 Depth in Metres 500 Width in Metres 13.26 Specific Gravity

[goldminer1956]

I am not a geologist or engineer, but you need to multiply the gm/ton grade, with the number of meters at that grade, then add the gm-meter numbers up for each drill hole. I then added up the number of meters multiplied by ave gm-meter for each drill hole get an average grade in gm/ton, get an average number of gm x meter for all the drill holes then apply that to a cube 4000m x 400m x 500 m deep

[Ivorygull]

I'm no geologist or engineer either goldminer1956, so that's why I was asking what others thought. Thanks for your input.