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Royal Nickel Corp. RNKLF



GREY:RNKLF - Post by User

Comment by goldhunter11on Apr 06, 2019 4:05pm
194 Views
Post# 29592329

RE:Western Flanks repost, understand what RNX is while it cheap

RE:Western Flanks repost, understand what RNX is while it cheapNEWBIE,
This is one good way to provide a napkin estimate for the Western Flank using Figure 7.8 of their ol 2016 PEA report. As I understand it you use L x D x W x s.g.x grade/31. Below I simply repeat your calculation just to verify the results. Comments will follow below.

Assumptions (units as labelled; and I use metric tonne = 1000kg = 1Mg; 1oz =31g)
- L = 900m
- D = 250m
- W= average 30m (ranging from 20 - 60m)
- s.g. 3 (I would use 2.7- 2.8, but 3 is fine)
Tonnage: 900 x 250x 30x3 = 20.25 M tonnes
- grade: 4gpt
20.25M x4/31 = 2.6MozAu (this checks out your results)

Comments on the assumptions and results
- L: Could be optimistic, since mineralization is not expected to be uniform, so length could be (arbitrarily) reduced by a factor of 2 (to be conservative), until additional drill results prove otherwise.
- Depth: 250m seems to be fine based on the "old" results (Figure 7.8) and new results Jan and Feb 2019 NRs.
- Width: 30m could be too conservative. If the last "pipe" (Smith) is included, the with would be around 80m (from Winchester pipe to Smith). In addition, if the x-section is moved NW (see inset) the width seem to get wider (~100m), but we need more data to confirm this. Hoever, the width could be increased by a factor of 2 (which would cancel the reduction of 2 for a shorter strike length.
- Grade: This could be an important factor... 4gpt seems fine, based on current results. If RNX could find more coarse gold with high to bonanza grades, as you have indicated, then the RE could sky rocket. Grade doe not have to be too high, something like what they have at Kirkland Lake Swan Zone would be good enough for RNX. 16 gpt would give us a factor of 4, i.e., 4 x 2.6M = ~10.4 MozAu. I would be happy to take 10% of that (i.e. 1Moz) for the Western Flank.

Note: My previous estimate using a box drawn around all the red and shocking dot in Figure 2 of the 25Feb NR came up with a similar number( about 1Moz) for the Western Flank. In other words two different approaches produced similar results.
Then the old RE in the 2016 PEA, and the new RE for the A-zone would need to be included for the total RE of BH (Fig 2 in the 25Feb 2019 NR shows the new drill results sit outside the JORC boundaries used in the 2016 PEA report).
GH11
-----------------------------------


NEWBIEVESTOR wrote:

https://ibb.co/Jq5t3t2

 

Understanding the bulk tonnage significant potential at the western flanks shear zone

 

Here is how to calculate a rough estimate at what could be at the WF. Visualize it as a 3D box. The length of the structure is currently defined at 900 meters and remains open at both ends. 

 

The depth of the mineralization is currently estimated at 250 meters and remains open because nothing has been drilled deeper yet.

 

The mineralization is in 6 vertical structures that vary in size and length of the ore body. As seen in the picture there are drill holes with intersections through each structure that total over 40 meters, most recently WFN-065 hole totals almost 60m gold mineralization. You can also see there are narrower parts of the shear zone that are likely under 20 meters. For our “rough” calculation we’ll say 30 meters is the average.

 

So from what we KNOW our box is 900m x 250m x 30m= 6.75 million. There are approximately 3 tons per sq/m = 20.25 million tons. 

 

The average grade is what we’re still finding out. Using 4g/t dividing by 31 to convert to ounces is 2.6 million oz.

 

What we still don’t know is the depth and length of the shear zone. What if it still extends another 300m and more than doubles in depth? There could be the potential for 10 million oz. This also doesn’t account for the pyritic sediment crossing through the shear zone creating the bonanza discoveries.



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