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IAMGOLD Corp T.IMG

Alternate Symbol(s):  IAG

IAMGOLD Corporation is a Canada-based intermediate gold producer and developer. The Company’s principal activities are the exploration, development and operation of gold mining properties in North America and West Africa. Its projects include Côté Gold, Essakane, and Westwood. The Côté Gold Mine is a large-scale, generational open pit operation located between Sudbury and Timmins in central Ontario. The Essakane project is West Africa’s 6th largest gold mine located in Burkina Faso (West Africa) approximately 330 kilometers northeast of the capital, Ouagadougou. The Westwood Complex includes the high-grade underground mine and satellite open pits located near Rouyn-Noranda in Quebec. The Company also owns a 100% interest in the Nelligan Gold Project, located 60Km southwest of Chibougamau, Quebec, Canada.


TSX:IMG - Post by User

Bullboard Posts
Post by TERRIBLEon Jun 30, 2018 3:33pm
363 Views
Post# 28256160

hole 18-217, EOH sum.......

hole 18-217, EOH sum.......For anyone who might be interested…….
 
Re. previous post….
Below is a better link to the June 14 news release
 
https://www.iamgold.com/English/investors/news-releases/news-releases-details/2018/IAMGOLD-Continues-to-Intersect-High-Grades-at-Monster-Lake/default.aspx
 
above link is from the “Iamgold.com” site
 
to view the June 14 news release, right click on above link
….and on the drop-down menu left click on “open hyperlink”.
 
Then Scroll down to table 1…..drill hole data.
……………………
 
HOLE 18-217
 
As noted in table 1, Hole 18-217  has an EOH ( End Of Hole )  value of  279 m
& an “interval” sum of 9.60 m
 
279/9.60 = 29.0625
 
The above ratio  indicates that this EOH includes  one m of  interval (core)  for every 29.0625 m of EOH 
 
  ( 1/9.60 = 29.0625/EOH) = 279
…………….
Note that,The 0.80 interval core (included in the  6.10 core) is graded at  at 251 g/t  Au and as previously calculated, one tonne of this core would have a value of $ 13,621 (in the ground)
 
251 g/t equates to  8.069 ozs /t   (251/31.1035)
……………………………..
 
 
 
From previous posting:
 
The EOH sum (from  news release)  = 12,016 m approx. = 12 KM = 7.466 MILES
Sum of core (interval) 107 m approx. = 351 FEET
12016/107 = 112.29


The above ratio  indicates that this EOH includes  one m of  interval (core)  for every 112.29 m (of EOH) 
 
 

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