try to do a math on nqe current depositafter listening david's interview, he mentioned what we have so far and anybody can do a simple math to estimate the current deposit, but i can't hear clearly , can somebody pay attention to the interview at 15' 10, when he said "you have to consider one thing.." and later he mentioned the orebody demention, i just heard 150 meters in depth and 150 meters in width, what is in length ? can somebody hear that ?
If we know the demention of the orebody, then we can do the math, suppose the length is also 150 meters, then the volume of the orebody is : 150X150X150 = 3375000 (m3) , the density of ore is 3 tonn/m3 as said by david in the interview, so the tonnage of the current orebody is 3375000 X 3 = 10125000 tons. suppose the average grade is 40g/t , this is also the grade of old Selbaie mine nearby, then our deposit is :
10125000 X 40 = 405000000 g = 12.85 million ounces.
So the key fact is the length of the orebody, can somebody listen that interview again and pay attention to the point after 15' 10.