Western Flanks post from 4 months ago
Understanding the bulk tonnage significant potential at the western flanks shear zone
Here is how to calculate a rough estimate at what could be at the WF. Visualize it as a 3D box. The length of the structure is currently defined at 900 meters and remains open at both ends.
The depth of the mineralization is currently estimated at 250 meters and remains open because nothing has been drilled deeper yet.
The mineralization is in 6 vertical structures that vary in size and length of the ore body. As seen in the picture there are drill holes with intersections through each structure that total over 40 meters, most recently WFN-065 hole totals almost 60m gold mineralization. You can also see there are narrower parts of the shear zone that are likely under 20 meters. For our “rough” calculation we’ll say 30 meters is the average.
So from what we KNOW our box is 900m x 250m x 30m= 6.75 million. There are approximately 3 tons per sq/m = 20.25 million tons.
The average grade is what we’re still finding out. Using 4g/t dividing by 31 to convert to ounces is 2.6 million oz.
What we still don’t know is the depth and length of the shear zone. What if it still extends another 300m and more than doubles in depth? There could be the potential for 10 million oz. This also doesn’t account for the pyritic sediment crossing through the shear zone creating the bonanza discoveries.
As you can see I called it right, drills have only hit a portion of WF and we at 1 million oz. Good post for those that don’t understand what WF is