RE:RE:re.re.un autre Hello 612 and everyone except the trolls
Remember, I am not a geologist, which is training having a dial order for the exercise of this profession, the determination of a resource for their income.
So I can only share hypotheses with you without it having any potential value.
There are rules to define a resource such as a minimum mesh size, a cutoff level, etc.
We can have fun among ourselves and make our assumptions though. and that would be up for discussion and improvement
They owe us a volume to determine a mass in which we will apply a gr/t
For the volume you need to get an idea of the shape of this mass
The latest press release tells us that the mass has a length of more than 400 meters along the dip. and in the description of the sluice we had laterally one of more than 120 meters:
The 2018 and 2019 drilling programs targeting the Eclipse Zone allowed Sirios to define the near-surface high-grade Eclipse Zone approximately 120 m laterally, 2 to 6 meters wide and over 250 m deep (open in depth). These drillings generated several high and very high grade gold intervals (see longitudinal on slide 7).
We can hypothesize that the bottom of this mass is the same length as laterally on the surface and the two sides of the dip are also equal (which we are completely unaware of)
we therefore have a min of 400m by 120 m and a thickness is missing, for this on the soundings which cross eclipse these are specifically identified in the communicate,, if we take them all, we can determine an average thickness, and thus determine a gr in proportion to their length.
As the length varies from less than 1 meter to more than 10 meters I fixed 4 meters for the thickness which I believe may be what could be drilled by a slicer (but I don't know)
thus all samples of less than 4 meters were complete with a gr at 0.. Thus a sample of 1 meter at 2 gr was complete with a 4 meters at 0 gr.
once compiler I therefore arrive with an average gr reflect of a little more than 10 gr per ton.
the flight is therefore 400 by 120 m by 4 m
tons is 2700 kg per cubic meter / 2000kg
grams per ton 10
this calculation gives me 150,000 onc