Post by
Wangotango67 on Mar 02, 2023 1:58pm
I'll take a poke at the resource calc -
1400 meter strike
x 350 meter width at surface
x 225 meter depth intercepts average ( some 300 meter thick
x 2.648 factor ore weight per ( silical has a 2.648 mass g/cm = 2648 tonne
= 291,942,000
x 5.5 lbs nickel / 0.25 % nickel per tonne
= 1,605,681, 000 bil pounds
Heavier ore weight using - 3.5 x factor
1400 m
x 350 m width
x 250 m depth
x 3.5 ore weight
= 428,750,000
x 5.5 pounds nickel per tonne 0.25 %grade
= 2,358,125,000 billion pounds
Without seeing the calculation for resource...
I would hazzard the guess and say...
the ore weight of 3.5x factor would be the way calculate the pounds of nickel
Anyone else ?
They also have a historical - W4 - zone with - 1% nickel
677,000 tonnes... which to my knowledge are drilling to bring upto CIM standards.