Post by
CdnBadger on Sep 05, 2019 8:17pm
Math
Could someone who knows geo dontje math for me here. I don't know how to work it out. Hypothetically if the entire fault was in fact the strike length and we were getting say 2 grams per ton.(or is there a more accurate conservative number). Like what could the potential of this thing be? In my head it seems massive but just what are we actually looking at here? Even if it was only the 3.5 km combined even that seems pretty big. Can someone help get a grasp on the numbers or explain/send me somewhere so I can do the work myself. Thanks in advance. I don't mind doing some heavy lefting so feel free to point me towards some heavy reading.
Comment by
BILLMINER on Sep 05, 2019 8:40pm
Many more ozs than seeking alpha pot man mentioned . Lol. Obvious paid agenda . They will block out a million or two ozs in the low grade material .just my opinion .
Comment by
allenbow on Sep 05, 2019 8:45pm
and that is just for each discovery so far.. :)
Comment by
Ggallant2000 on Sep 06, 2019 5:56am
Great post! Do you post at ceo.ca? If not, could I post a link?
Comment by
touareg on Sep 06, 2019 9:02am
Thank you.. I don't post there.. maybe I should SH is a pain in the boot.. Sure share away.
Comment by
KL8877 on Sep 06, 2019 11:41am
Someone do the math again to validate. This thing could actually reach 100 million ounces...
Comment by
CdnBadger on Sep 06, 2019 11:16am
Was Chris not encouraging us to do our own math? Your point is well taken and I get it but I felt Chris was hinting at doing the math to understand the scope of it. Did I misunderstand what he waa saying?
Comment by
goindeeper on Sep 05, 2019 11:55pm
Total In Situ Value = (volume of deposit)(specific gravity of host rock)(average g/t of deposit)(in situ value of one gram of gold based on purchases of similar deposits) Make sure your units are consistent i.e. use metres and grams all the way through or you have to include the conversion factors in your calculation.