Post by
Kewl002 on Jul 01, 2022 1:42am
Any mathematicians on this BB????
My question (purely for the fun of it).....
if NFG gained gov't approval for a 10,000 ton bulk sample from a sweet spot of the Keats zone (pick one as there are many) and was able to complete the extaction (open pit?) and have it processed at a local mill (say 95% recovery -- how much gold would be realized from the bulk sample @ $1,800/oz avg?
Would that be sufficient (minus costs of course) to fund 2023 exploration without further share dilution?
Anyone have the skill set to do a back of envelope style calculation?
Comment by
braindeadoldguy on Jul 01, 2022 3:57am
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Comment by
Retiredgeo on Jul 01, 2022 6:42am
The only near surface assay that we have is 22-593 grading 9.12 g/t. 10,000 tonnes of 9.12 g/t is 91,200 g or 2,932 oz. Assuming 95% recovery that is 2,785 oz. Assuming $1800/oz that is $5 million USD gross value. The answer to your question is no. They need a much sweeter spot than published to date.
Comment by
Retiredgeo on Jul 01, 2022 7:32am
At 2.7 tonnes/metre 10,000 tonnes = 3,703 m3. That is the equivalent of a 20x20x9.25 m pit. I'm not sure how you expect to access ore 22 m down? The only near surface result that we have is 22-593.
Comment by
rgvgolf on Jul 01, 2022 9:08am
Well said mega. You may need two trucks loading at a rate of 7 loads per hour 12 hours per day for 3 days. keeep up the good work of common sense reporting RGV
Comment by
Retiredgeo on Jul 01, 2022 9:32am
You are misreading the numbers. Hole 22-593 also contains 42.6 g/t over 11.75 m starting at 20.5 m depth. Same problem. You need to greatly expand the bulk sample to dig a pit that deep. Your excavator isn't going to make the cut. Somewhere, they probably have high grade just below their boots but they haven't published such findings yet.